28-(10-b)^2=-b^2

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Solution for 28-(10-b)^2=-b^2 equation: 



28-(10-b)^2=-b^2

We move all terms to the left:

28-(10-b)^2-(-b^2)=0

We add all the numbers together, and all the variables

-(-b^2)-(-1b+10)^2+28=0

We get rid of parentheses

b^2-(-1b+10)^2+28=0

We move all terms containing b to the left, all other terms to the right

b^2-(-1b+10)^2=-28

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